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A force which varies with time t as \overline{F} = 3\widehat{i}+5t\widehat{j}N acts on a body due to which its position varies with time t as \overline{S} = 2\widehat{i}-5t^2\widehat{j} where t is in seconds. Workdone by this force in initial is nearly        

Option: 1

-17J


Option: 2

+20J


Option: 3

-27J


Option: 4

+30J


Answers (1)

best_answer

W=\int \overline{F}.d\overline{s}

      =\int \left ( 3\widehat{i}+5t\widehat{j} \right ).(-10t\widehat{j})

     =-50\int_{0}^{1}t^2=50\left [ \frac{t^3}{3} \right ]_0^1

     =-50\frac{1}{3}=\frac{-50}{3}J

\overline{S}=2\widehat{i}-5t^2\widehat{j}

\frac{d\overline{s}}{dt}=0-10t\widehat{j}

d\overline{s}=-10t(\widehat{j})dt

Posted by

vishal kumar

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