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A gas is filled in a 10L container with a pressure of 2 atm at \small 0^{\circ}C. At what temperature (in oC) will the pressure inside the container will be 2.5 atm?

Option: 1

68.25


Option: 2

73.67


Option: 3

65.45


Option: 4

56.98


Answers (1)

best_answer

According to Gay-Lussac’s law, we have:

\\\mathrm{\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}}

Now,

\mathrm{P_1=2\ atm,P_2=2.5 \ atm}


And, \mathrm{T_1=273\ K}

\mathrm{T_2=\frac{2.5\times273}{2}=341.25\: K\: or\: \: 68.25^{\circ}C}

 

Posted by

Ritika Kankaria

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