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A gas mixture contain $35\%$ $\mathrm{He}$ and $\mathrm{65 \% \, \mathrm{CH}_{4}}$ by volume at a gives temperature and pressure.

The Percentage by mass of methane in the mixture?
Option: 1
$8%$

Option: 2
$-88%$

Option: 3
$-85%$

Option: 4
$83 %$

Answers (1)

best_answer

Molar mass at $\mathrm{He= 4, CH_{4}= 16}$

$\mathrm{\therefore }$ Mass $\mathrm{% }$ at methane in the mixture $\mathrm{\Rightarrow }$
$\mathrm{\Rightarrow \frac{65 \times 16}{35 \times 4+65 \times 16} \times 100 }$
$\mathrm{\Rightarrow \frac{1040}{140+1040} \times 100 }$
$\mathrm{\Rightarrow \frac{1040}{1180} \times 100 }$

$\mathrm{=88 \% }$

Posted by

Rishi

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