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  • A geostationary satellite orbits around the earth in a circular orbit of radius <img alt="36000\: \mathrm{km}" src="https://entrancecorner.oncodecogs.com/gif.latex?36000%5C%3A%20%5Cmathrm%7Bkm%7D"

A geostationary satellite orbits around the earth in a circular orbit of radius 36000\: \mathrm{km}. Then the time period of a spy satellite orbiting a few hundred kilometre above the earth's surface (\mathrm{R_{earth}} \mathrm{=6400 \mathrm{~km}} ) will approximately be
 

Option: 1

\mathrm{\frac{1}{2}h}


Option: 2

\mathrm{1h}


Option: 3

\mathrm{2h}


Option: 4

\mathrm{4h}


Answers (2)

best_answer

\mathrm{\mathrm{v}=\sqrt{\mathrm{gR}}=7.9 \mathrm{kms}^{-1}, and}

\mathrm{ \mathrm{T}=\frac{2 \pi \mathrm{R}}{\mathrm{v}}=\frac{2 \pi 6400 \times 100}{7900} }

\mathrm{ =84.79 \text { minute } }

is the time period of satellite revolving very close to earth's surface. So time period of spy satellite must be slightly greater and so \mathrm{ C } is the appropriate answer.

Hence option 3 is correct.

Posted by

HARSH KANKARIA

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1h

Posted by

Guru G

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