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  • A hydrogen atom in its ground state absorbs wavelength. Calculate to which shell the electr

A hydrogen atom in its ground state absorbs 1215.6 \mathrm{~A}^{\circ} wavelength. Calculate to which shell the electron will be excited after absorbing this wavelength or photon.

Option: 1

\mathrm{n=4}


Option: 2

\mathrm{n=3}


Option: 3

\mathrm{n=2}


Option: 4

\mathrm{n=1}


Answers (1)

\lambda=1215^{\circ} 6 A^{\circ}

\mathrm{E_{a b s}=\frac{h c}{\lambda}=\frac{12400 \mathrm{eV}-A^{\circ}}{1215.6 A^{\circ}}=10.2 \mathrm{eV}}

It electron in ground state absorb energy equivalent to 10.2 eV, it will jump to \mathrm{n=2} energy level.

\therefore Option (3) is the right answer.

Posted by

Ramraj Saini

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