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  • A large tank is filled with water (density <img alt="\mathrm{=10^3 \mathrm{~kg} /\mathrm{m}^3}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%3D10%5E3%20%5Cmathrm%7B%7Ekg%7D%20/

A large tank is filled with water (density \mathrm{=10^3 \mathrm{~kg} /\mathrm{m}^3} ). A small hole is made at a depth \mathrm{10 \mathrm{~m}} below water surface. The range of water issuing out of the hole is Ron ground. What extra pressure must be applied on the water surface so that the range becomes \mathrm{2 \mathrm{R} (take 1 \mathrm{~atm}=10^5 \mathrm{~Pa}} and \mathrm{\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2} ) :

Option: 1

9 atm


Option: 2

4 atm


Option: 3

5 atm


Option: 4

3 atm


Answers (1)

best_answer

\mathrm{ R=\sqrt{2 \mathrm{~g} \times 10} \sqrt{\frac{2 \mathrm{H}}{\mathrm{g}}} }                  ............(1)

Now  \mathrm{\rho g h+P_0+P_E=P_0+\frac{1}{2} \rho V^2}
\mathrm{ \begin{aligned} & \Rightarrow V^2=2 g h+\frac{2 P_E}{\rho} \\ & \Rightarrow R^{\prime}=\sqrt{(2 g 10)+\left(\frac{2 P_E}{\rho}\right)} \sqrt{\frac{2 H}{g}} \end{aligned} }                   ...........(2)
From (1) & (2) \mathrm{\mathrm{P}_{\mathrm{E}}=3 \mathrm{~atm}.}

Posted by

manish painkra

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