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  • A layer of benzene floats on water. If the angle of incidence of the light entering benzene from air is <img alt="60^{\circ}" src="https://entrancecorner.oncodecogs.com/gif.latex?60%5E%7B%5Ccirc%7D

A layer of benzene floats on water. If the angle of incidence of the light entering benzene from air is 60^{\circ}, then the angle that light makes with normal in water is
(Refractive index of water =4 / 3)

Option: 1

30^{\circ}


Option: 2

\sin ^{-1}\left(\frac{3 \sqrt{3}}{8}\right)


Option: 3

\sin ^{-1}\left(\frac{1}{\sqrt{3}}\right)


Option: 4

 Data not sufficient


Answers (1)

best_answer

Here one might be tempted to think that since the refractive index of
benzene is not given, (D) is correct. But actually we do not need this data.

\mu_{1} \sin \mathrm{i}_{1}=\mu_{2} \sin \mathrm{i}_{2}=\mu_{3} \sin \mathrm{i}_{3}

\therefore \sin \mathrm{i}_{3}=\frac{\mu_{1} \sin \mathrm{i}_{1}}{\mu_{3}}=\frac{3 \sqrt{3}}{8}

Posted by

Kuldeep Maurya

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