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  • A liquid flows through two capillary tubes A and B connected in series. The length and radius of B are twice those of A. The ratio of the pressure difference across A to that ac

A liquid flows through two capillary tubes A and B connected in series. The length and radius of B are twice those of A. The ratio of the pressure difference across A to that across B is

Option: 1

8


Option: 2

4


Option: 3

2


Option: 4

1


Answers (1)

best_answer

\mathrm{ Q_1=\frac{\pi P_1 r_1^4}{8 \eta l_1} \text { and } Q_2=\frac{\pi P_2 r_2^4}{8 \eta l_2} }

Since the tubes are connected in series, \mathrm{ Q_1=Q_2}

or                     \mathrm{\quad \frac{\pi P_1 r_1^4}{8 \eta l_1}=\frac{\pi P_2 r_2^4}{8 \eta l_2}}

or             \mathrm{\quad \frac{P_1}{P_2}=\left(\frac{l_1}{l_2}\right) \times\left(\frac{r_2}{r_1}\right)^4=\left(\frac{1}{2}\right) \times 2^4=8}

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Shailly goel

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