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  • A man with a parachute after bailing out  falls 100 m without any kind of resistance; when he opens the parachute it deaccelerates with <img alt="5ms^{-2};" src="https://entranc

A man with a parachute after bailing out  falls 100 m without any kind of resistance; when he opens the parachute it deaccelerates with 5ms^{-2};and when he reaches the ground his speed is 2 m/s; the height at which he bails out is 

Option: 1

299.6 m


Option: 2

300 m


Option: 3

100 m

 


Option: 4

298.7 m 


Answers (1)

best_answer

Firstly the man falls under the gravity 

 u^{2}=2gh=2\times 10\times 100 =2000

Now we need to use 

v^{2}=u^{2}-2as

2^{2}=2000-2\times 5\times h

h = 199.6 \: m

Total height = \left ( 100+199.6 \right )=299.6\: m

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