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A metal M readily forms water soluble sulphate \mathrm{MSO}_{4},water insoluble hydroxide \mathrm{M}(\mathrm{OH})_{2} and oxide MO which becomes inert on heating. The hydroxide is soluble in \mathrm{NaOH}. The \mathrm{M} is

Option: 1

\mathrm{Be}


Option: 2

\mathrm{Mg}


Option: 3

\mathrm{Ca}


Option: 4

\mathrm{Sr}


Answers (1)

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As we move down the group 2, the solubility of sulphates decreases. Be and Mg sulphates are highly soluble due to high enthalpy of solvation of smaller \mathrm{Be}^{2+}and \mathrm{Mg}^{2+}ions.

\mathrm{BeO} and \mathrm{MgO} are non-reactive on heating, hence they are used in lining furnaces.

\mathrm{Be}(\mathrm{OH})_{2}  is almost insoluble in water & amphoteric in nature but the hydroxides of \mathrm{Mg},\mathrm{Ca} and \mathrm{Sr} are basic. Hence \mathrm{Be}(\mathrm{OH})_{2} will dissolve both in acids and alkali.

\mathrm{Be}(\mathrm{OH})_{2}+2 \mathrm{NaOH} \rightarrow \mathrm{Na}_{2} \mathrm{BeO}_{2}+2 \mathrm{H}_{2} \mathrm{O}

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Pankaj

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