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A metal on combustion in excess air forms \mathrm{x . x} upon hydrolysis water yields \mathrm{\mathrm{H}_2 \mathrm{O}_2\: and \: \mathrm{O}_2} along with another product. The metal is -
 

Option: 1

\mathrm{Li}


Option: 2

\mathrm{Mg}
 


Option: 3

\mathrm{Rb}
 


Option: 4

\mathrm{Na}


Answers (1)

best_answer

Metal is \mathrm{Rb} (rubidium). In excess of air, it forms \mathrm{\mathrm{RbO}_2}. \mathrm{x}  is superoxide that hare \mathrm{\mathrm{O}_2{ }^{-}} ion. It is due to the stabilisation of large anion by large cations through lattice energy effects.

The reaction involved:-

\mathrm{Rb+O_{2}\rightarrow RbO_{2}} (Superoxide)

\mathrm{2RbO_{2}+2H_{2}O}\rightarrow \mathrm{2RbOH+H_2O_2+O_2}

Hence option 3 is correct.

Posted by

HARSH KANKARIA

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