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A metal rod of 1m in length is dropped exactly vertically onto a hard metal floor. With an oscilloscope, it is determined that the impact produces a longitudinal wave of 1.2 kHz frequency. the speed of sound in the metal rod is:

Option: 1

600


Option: 2

2400


Option: 3

1200


Option: 4

400


Answers (1)

best_answer

\lambda = 2l     (for the fundamental wave in the rod of length l)

\therefore velocity of sound, v = n\lambda

                                    = 1.2 * 10^{3} * 2 * 1 = 2400 m/s

Posted by

Irshad Anwar

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