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  • A particle of mass 1kg is moving in the X-Y plane with a velocity of 2m/s along the straight line y=x+2. Find its angular momentum about its origin.<img alt="" src="https://cdn.entrance360.com/medi

A particle of mass 1kg is moving in the X-Y plane with a velocity of 2m/s along the straight line y=x+2. Find its angular momentum about its origin.

Option: 1

\sqrt{2} \mathrm{~kg}-m^2-\mathrm{s}^{-1}


Option: 2

2 \sqrt{2} k g-m^2-s^{-1}


Option: 3

3 \sqrt{2} \mathrm{~kg}-\mathrm{m}^2-s^{-1}


Option: 4

4 \sqrt{2} \mathrm{~kg}-\mathrm{m}^2-\mathrm{s}^{-1}


Answers (1)

\text { In } \triangle P Q R \text {, }

\begin{aligned} & \angle Q R P=90^{\circ} \\ & \angle R Q P=45^{\circ} \end{aligned}

\sin 45^{\circ}=\frac{R P}{P R}

R P=P Q \sin 45^{\circ}=2 \times \frac{1}{\sqrt{2}}=\sqrt{2} \mathrm{~m}

L=m v r=(1)(2)(\sqrt{2})=2 \sqrt{2} \mathrm{~kg}-\mathrm{m}^2-\mathrm{s}^{-1}

Posted by

Ramraj Saini

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