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  • A particle of mass, m = 2 kg is moving with a speed v along a straight line given by y = 2x + y. If the angular momentum of the particle about the origin is 16<img alt="\sqrt{5}" src="https://entra

A particle of mass, m = 2 kg is moving with a speed v along a straight line given by y = 2x + y. If the angular momentum of the particle about the origin is 16\sqrt{5} kg-m2-s-1, then, the speed of the particle will be:

Option: 1

1 m/s


Option: 2

10 m/s


Option: 3

3 m/s


Option: 4

4 m/s


Answers (1)

best_answer

\frac{r_{p}}{2} = \sin \theta

\tan \theta = 2

\sin \theta = \frac{2}{\sqrt{5}}

r_{p} = 2 \sin \theta

r_{p} = 2 * \frac{2}{\sqrt{5}}

r_{p} = \frac{4}{\sqrt{5}}

mvr_{p} = L

v = \frac{L}{mvr_{p}}

v = \frac{16\sqrt{5}}{2 * \frac{4}{\sqrt{5}}}

v = \frac{16 * 5}{8}

v = 10 m/s

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