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A person of mass 60 \mathrm{~kg} wants to lose 5 \mathrm{~kg} by going up and down a 10 \mathrm{~m} high stairs. Assume he burns twice as much fat while going up than coming down. If 1 \mathrm{~kg} of fat is burnt on expanding 7000 kilo calories, how many times must be go up and down to reduce his weight by 5 \mathrm{~kg}?

Option: 1

10.5 \times 10^{3}


Option: 2

24.3 \times 10^{3}


Option: 3

16.3 \times 10^{3}


Option: 4

9 \times 10^{3}


Answers (1)

best_answer

\mathrm{5 \times 7000 \times 10^{3} \times 4.2 \mathrm{~J}=60 \times 15 \times 10 \times N}

\mathrm{N=\frac{21 \times 7 \times 10^{6}}{900}=\frac{147}{9} \times 10^{3}=16.3 \times 10^{3} \text { times } .}

Posted by

Divya Prakash Singh

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