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  • A planet moves around the sun. At a point it is closest from the sun at a distance <img alt="\mathrm{

A planet moves around the sun. At a point \mathrm{P} it is closest from the sun at a distance \mathrm{d_1} and has a velocity \mathrm{V}_1. AT another point \mathrm{Q}, when it is farthest from the sun at a distance \mathrm{\mathrm{d}_2} its speed will be
 

Option: 1

\mathrm{\frac{d_1^2 V_1}{d_2^2}}


 


Option: 2

\mathrm{\frac{\mathrm{d}_2 \mathrm{~V}_1}{\mathrm{~d}_1}}
 


Option: 3

\mathrm{\frac{\mathrm{d}_1 \mathrm{~V}_1}{\mathrm{~d}_2}}


Option: 4

\mathrm{\frac{\mathrm{d}_2^2 \mathrm{~V}_1}{\mathrm{~d}_1^2}}


Answers (1)

best_answer

Angular momentum is conserved

\mathrm{\therefore \quad \mathrm{mv}_1 \mathrm{~d}_1=\mathrm{mv}_1 \mathrm{~d}_2 }

\mathrm{\quad \mathrm{v}_2=\frac{\mathrm{v}_1 \mathrm{~d}_1}{\mathrm{~d}_2}}

Hence option 3 is correct.



 

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Sayak

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