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A projectile is fired at an angle of 45^{\circ} with the horizontal. Find the work done by gravitational force from point of projection till the point where it reaches highest point (take maximum vertical height = H and horizontal range =R) 

Option: 1

mg(H+R)


Option: 2

\frac{-mgH}{2}


Option: 3

-mg(H+R)


Option: 4

-mgH


Answers (1)

best_answer

Gravitational force = -mg(-\widehat{j})

Dsiplacement of projection = \frac{R}{2}(\widehat{i})+H(\widehat{j})

WorkDone = \overline{F}.\overline{s}=mg(-\widehat{j}).\left ( \frac{R}{2}\widehat{i}+H\widehat{j} \right )

                   =mgH

Posted by

Divya Prakash Singh

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