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A rectangular tank is placed on a horizontal ground and is filled with water to a height \mathrm{H} above the base. A small hole is made on one vertical side at a depth D below the level of the water in the tank. The distance x from the bottom of the tank at which the water jet from the tank will hit the ground is

Option: 1

\mathrm{2 \sqrt{D(H-D)}}


Option: 2

\mathrm{2 \sqrt{D H}}


Option: 3

\mathrm{2 \sqrt{D(H+D)}}


Option: 4

\mathrm{\frac{1}{2} \sqrt{\mathrm{DH}}}


Answers (1)

best_answer

\mathrm{\begin{aligned} & \Delta \rho g=\frac{1}{2} \rho v^2 \\ & v=\sqrt{2 D g} \\ & x=v \sqrt{\frac{2(H-D)}{g}}=2 \sqrt{D(H-D)} \end{aligned}}

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