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  • A reversible engine takes in heat from a reservoir of heat at &nbsp

A reversible engine takes in heat from a reservoir of heat at 527^{\circ} \mathrm{C}  and gives it to the sink at 127^{\circ} \mathrm{C} . How many calorie/s it shall take from the reservoir to do a work of 750 \mathrm{~W}.

Option: 1

257 \mathrm{cal} \mathrm{s}^{-1}


Option: 2

357 \mathrm{cal} \mathrm{s}^{-1}


Option: 3

1500 \mathrm{cal} \mathrm{s}^{-1}


Option: 4

None of these


Answers (1)

best_answer

Efficiency of a Carnot's engine is given by

\mathrm{\quad \eta =\frac{W}{Q}=1-\frac{T_{2}}{T_{1}} }
\mathrm{\Rightarrow \quad W =\left(1-\frac{T_{2}}{T_{1}}\right) Q }

Substituting

\mathrm{T_{2}=127+273=400 \mathrm{~K} }
\mathrm{T_{1}=527+273=800 \mathrm{~K} }

\mathrm{ Q=2 W=\frac{2 \times 750}{4.2}=357.1 \mathrm{cal} / \mathrm{s}}

Posted by

shivangi.bhatnagar

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