Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

A ring of radius R is rolling over rough horizontal surface with velocity $v_0$ . Two points located at A and B on rim of ring. The angular velocity of point A w.r.t. point B will be

Option: 1
$\frac{v_0}{2R}$

Option: 2
$\frac{v_0}{R}$

Option: 3
$\frac{v_0}{\sqrt{2}R}$

Option: 4
$\frac{\sqrt{2}v_0}{R}$

Answers (1)

best_answer

Answer (2)

$\\V_{AB}=2V_0\\ \omega _{AB}=\frac{V_{AB}}{2R}\\$

$\\=\frac{2V_{0}}{2R}\\=\frac{V_{0}}{R}$

Posted by

jitender.kumar

View full answer

NEET 2024 Most scoring concepts

Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Karnataka NEET UG Counselling 2025: KEA to hold special stray vacancy round for dental seats on December 31

anam-khan

Gujarat NEET UG 2025 special stray round seat allotment result out; 93 candidates listed

anam-khan

MP NEET PG 2025 round 2 allotment result declared; 1287 secure MD, MS seats

Latest Question