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  • A simple pendulum of length of , with a bob of mass <img alt="1 \mathrm{~kg}" src="https://e

A simple pendulum of length of 5 \mathrm{~m}, with a bob of mass 1 \mathrm{~kg}, is in simple harmonic motion. As it passes through its mean position, the bob has a speed of 5 \mathrm{~m} / \mathrm{s}. The net force on the bob at the mean position is -
 

Option: 1

0
 


Option: 2

2.5 \mathrm{~N}
 


Option: 3

5 \mathrm{~N}
 


Option: 4

25 \mathrm{~N}


Answers (1)

best_answer

\mathrm{Net \: force =\mathrm{ma}}

\mathrm{\left(F_c-m g\right) =m a^r }

\mathrm{F_{\text {net }} =\frac{m v^2}{r} }

          \mathrm{=\frac{1 \times(5)^2}{5} }

          \mathrm{=25 / 5=5 \mathrm{~N} }

Hence option 3 is correct.





 

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