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A small steel ball of radius r experiences a viscous force F when it is falling in a jar of glycerine with terminal velocity v. The viscons force experienced by a steel ball of radius \mathrm{r / 2} falling in glycerine with terminal velocity \mathrm{v / 2} is

Option: 1

\mathrm{F}


Option: 2

\mathrm{\frac{F}{2}}


Option: 3

\mathrm{\frac{F}{4}}


Option: 4

\mathrm{\frac{F}{8}}


Answers (1)

best_answer

\mathrm{ \begin{aligned} & F=6 \pi \eta r v \\ & \qquad F^{\prime}=6 \pi \eta\left(\frac{r}{2}\right) \times\left(\frac{v}{2}\right)=\frac{1}{4} \times 6 \pi \eta r v=\frac{F}{4} \end{aligned} }
So the correct choice is (c).

Posted by

shivangi.bhatnagar

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