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  • A small wooden ball of density  is immersed in water of density <img alt="\mathrm{\sigma}

A small wooden ball of density \mathrm{\rho} is immersed in water of density \mathrm{\sigma} to depth $h$ and then released. The height \mathrm{H} above the surface of water up to which the ball will jump out of water is

Option: 1

\mathrm{\frac{\sigma h}{\rho}}


Option: 2

\mathrm{\left(\frac{\sigma}{\rho}-1\right) h}


Option: 3

\mathrm{\text { h }}


Option: 4

\mathrm{Zero}


Answers (1)

best_answer

\mathrm{\begin{aligned} \Rightarrow & -\frac{4}{3} \pi r^3 \rho(H+h) g+\left(\frac{4}{3} \pi r^3\right) \sigma g h=0 \\\\ & -\rho g H-\rho g H+\sigma g h=0 \\\\ & g h(\sigma-\rho)=\rho g H \\\\ & H=\left(\frac{\sigma}{\rho}-1\right) h \end{aligned}}

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manish

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