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  • A sodium salt of an unknown an ion when treated with gives white precipitate only on boilin

A sodium salt of an unknown an ion when treated with \mathrm{MgCl}_2 gives white precipitate only on boiling. The an ion is -
 

Option: 1

\mathrm{\mathrm{SO}_4 ^{2-}}
 


Option: 2

\mathrm{\mathrm{HCO}_3^{-}}
 


Option: 3

\mathrm{\mathrm{CO}_3^{2-}}
 


Option: 4

\mathrm{\mathrm{NO}_3^{-}}


Answers (1)

best_answer

\mathrm{Mg}\left(\mathrm{HCO}_3\right)_2 on boiling decomposes to gire white preaptate of \mathrm{MgCO}_3 as -

\mathrm{ \mathrm{Mg}\left(\mathrm{HCO}_3\right)_2 \text { (aq) } \stackrel{\Delta}{\longrightarrow} \mathrm{MgCO}_3 \downarrow+\mathrm{H}_2 \mathrm{O}+\mathrm{CO}_2 \uparrow }

Hence option 2 is correct.

 

Posted by

Ritika Jonwal

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