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A solution containing  9.8 \mathrm{~g}  urea in one litre was found to be isotonic with  \mathrm{0.8 \%(\omega t / v o t)}  Solution of organic, non volatile solution. The molecular weight of latter is

Option: 1

8.96 \mathrm{gm} / \mathrm{mol}


Option: 2

3.62 \mathrm{gm} / \mathrm{mol}


Option: 3

1.92 \mathrm{gm} / \mathrm{mol}


Option: 4

4.89 \mathrm{gm} / \mathrm{mol}


Answers (1)

best_answer

Solution is isotonic So, \pi_1=\pi_2
\mathrm{\frac{n_1}{V_1} R T =\frac{n_2}{V_2} R T \text { \{Here R \& T \ are constant\} ~ } }
\mathrm{\left(\frac{\omega_1}{m_1 \times v_1}\right) =\left(\frac{\omega_2}{m_2 \times v_2}\right) }   Organic
\mathrm{\frac{9.8}{60 \times 1000} =\frac{0.8}{m_2 \times 1000} }

\mathrm{m_2=4.89 \mathrm{~g} / \mathrm{mol} }.

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Anam Khan

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