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  • A source emits electromagnetic waves of wavelength .One beam reaches the observer directly a

A source emits electromagnetic waves of wavelength 3 \mathrm{~m}.One beam reaches the observer directly and other after reflection from a water surface, travelling 1.5 \mathrm{~m} extra distance and with intensity reduced to 1 / 4 as compared to intensity due to the direct beam alone. The resultant intensity will be

Option: 1

\mathrm{(1 / 4) fold}


Option: 2

\mathrm{(3 / 4) fold}


Option: 3

\mathrm{(5 / 4) fold}


Option: 4

\mathrm{(9 / 4) fold}


Answers (1)

best_answer

We know that a phase change of \pi occurs when the reflection takes place at the boundary of denser medium. This is equivalent to a path difference of \lambda / 2.

\therefore Total phase difference =\pi-\pi=0

Thus the two waves superimpose in phase.

\text{Resultant amplitude }=\sqrt{1}+\sqrt{(1 / 4)}=\frac{3}{2} \sqrt{1}
\text{Resultant intensity }=\left(\frac{3}{2} \sqrt{1}\right)^{2}=\frac{9}{4} I=\frac{9}{4}\text{ fold}


 

Posted by

shivangi.shekhar

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