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  • A specific volume of  Requires 68 sec to diffuse out of a container. The time Required b

A specific volume of \mathrm{H}_2 Requires 68 sec to diffuse out of a container. The time Required by an equal volume of \mathrm{O}_2 to diffuse out under identical condition, is?

Option: 1

96 s


Option: 2

384 s


Option: 3

192 s


Option: 4

24 s


Answers (1)

best_answer

\mathrm{\frac{\mathrm{rO}_2}{\mathrm{rH}_2}=\sqrt{\frac{M H_2}{\mathrm{MO}_2}}=\sqrt{\frac{2}{32}}=\frac{1}{4}}

Posted by

Rishi

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