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  • A sphere starts rolling on rough inclined plane of inclination . Find its acceleration of C.M.?  <

A sphere starts rolling on rough inclined plane of inclination \theta. Find its acceleration of C.M.?
 

Option: 1

\mathrm{5 g \sin \theta}
 


Option: 2

\mathrm{\frac{7}{9} \sin \theta}
 


Option: 3

\mathrm{\frac{5}{7} g \sin \theta}
 


Option: 4

\mathrm{g \sin \theta}


Answers (1)

best_answer

using, \mathrm{a_{c m}=\frac{\text { unbalanced load }}{\text { total inertia }}}

                 \mathrm{ =\frac{m g \sin \theta}{m+\frac{I}{R^2}} }

                \mathrm{ =\frac{m g \sin \theta}{m+\frac{2}{5} \frac{m R^2}{R^2}}=\frac{5}{7} g \sin \theta }

Hence option 3 is correct.


 

Posted by

sudhir kumar

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