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  • A spherical surface of curvature R separates air  . The centre of curvature is in the glass.

A spherical surface of curvature R separates air (\mu=1.5) . The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O and P O=O Q. The distance PO is equal to

Option: 1

2R


Option: 2

5R


Option: 3

3R


Option: 4

1.5R


Answers (1)

best_answer

As   \mathrm{ \frac{\mu 2}{v}-\frac{\mu 1}{u}=\frac{\mu-1}{R} }
or  \mathrm{ \frac{1.5}{x}-\frac{1}{x}=\frac{1.5-1}{R} \Rightarrow x=\frac{2.5 R}{0.5}=5 R }
 

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chirag

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