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  • A steam engine whose source is at , takes 200 cal of heat and rejects 150 cal to th

A steam engine whose source is at 400 \mathrm{~K}, takes 200 cal of heat and rejects 150 cal to the sink. What is the temperature of the sink? 

Option: 1

800 \mathrm{~K}


Option: 2

400 \mathrm{~K}


Option: 3

300 \mathrm{~K}


Option: 4

None of these


Answers (1)

best_answer

\mathrm{\eta=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{200-150}{200}=\frac{1}{4}}

\mathrm{\eta=\frac{1}{4}=1-\frac{T_{2}}{T_{1}}}

This gives \mathrm{T_{2}=\frac{3}{4} T_{1}=\frac{3}{4} \times 400 \mathrm{~K}=300 \mathrm{~K}}

Posted by

rishi.raj

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