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  • A stretched string fixed at both ends has 'm' nodes, therefore length of the string will be -Option: 1 <img alt="(m-1)\frac{\lambda }{2}" src

A stretched string fixed at both ends has 'm' nodes, therefore length of the string will be -

Option: 1

(m-1)\frac{\lambda }{2}


Option: 2

\frac{m\lambda }{2}


Option: 3

\frac{(m+1)\lambda }{2}


Option: 4

None


Answers (1)

best_answer

For P numbers of loops in a stretched string, the length is given by 

l=\frac{P\lambda }{2} ......1

As,number of harmonies = number of loops = antinodes +1

Here, number of nodes = m

Number of antinodes = m-1 = P

Putting this value in equation 1 

l=\frac{(m-1)\lambda }{2}

 

Posted by

Ajit Kumar Dubey

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