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  • A string is hanging from a rigid support. A transverse ware pulse is set up at the free end. The velocity <img alt="\small v" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Csmall%20v"

A string is hanging from a rigid support. A transverse ware pulse is set up at the free end. The velocity \small v of the pulse related to the distance \small x covered by it is given as -

Option: 1

v \propto \sqrt{x}


Option: 2

v \propto x


Option: 3

v \propto \frac{1}{x}


Option: 4

None


Answers (1)

best_answer

Tension at at distance x from free end                                  

\begin{aligned} & T_x=\omega_x=m_x g=\mu x g \\ & \sqrt{\frac{T_x}{\mu}}=\sqrt{x g} \\ & v=\sqrt{x g} \\ & v \propto \sqrt{x} \end{aligned}

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