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  • A string is under tension so that its length is increased by  times its original lengt

A string is under tension so that its length is increased by \frac{1}{n} times its original length. The ratio of fundamental frequency of longitudinal vibrations and transverse vibrations will be 

Option: 1

1:n


Option: 2

n^2: 1


Option: 3

\sqrt{n}: 1


Option: 4

n: 1


Answers (1)

best_answer

Velocity of longitudinal wave = V_1=\sqrt{\frac{Y}{\rho}}

Velocity of transverse wave = V_2=\sqrt{\frac{T}{m}}=\sqrt{\frac{T}{\rho s}}

\therefore \frac{V_1}{V_2}=\sqrt{\frac{Y S}{T}}=\sqrt{\frac{Y}{(T / s)}}=\sqrt{\frac{Y}{Y\left(\frac{\Delta 1}{T}\right)}}=\sqrt{n}

\therefore \frac{f_1}{f_2}=\frac{v_1}{v_2}=\sqrt{n}: 1

 

 

Posted by

himanshu.meshram

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