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A tube of length 1m is filled completely with an incompressible liquid of mass 1kg and closed at both ends. The tube is rotated in a horizontal plane about one of its ends with a uniform angular velocity of 2rad/s. The force exerted by the liquid at the other end is- 

 

Option: 1

1N


Option: 2

2N


Option: 3

4N


Option: 4

8N


Answers (1)

best_answer

df=(\frac{M}{L})(dx)(x)w^{2}

Integrating both sides

\int df=\int (\frac{M}{L})(dx)(x)w^{2}\\\int df=(\frac{Mw^{2}}{L})\int_{0}^{l}xdx\\F=\frac{Mw^{2}}{L}\times\frac{L^{2}}{2}=\frac{Mw^{2}L}{2}\\F=\frac{(1)(2)^{2}(1)}{2}=2N

Posted by

Sanket Gandhi

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