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A tuning fork is vibrating at x Hz. The length of the shortest closed organ pipe that will resonate with the tuning fork will be 38 cm. (Take speed of. sound in air as  332 m/s.

 

Option: 1

218 Hz


Option: 2

259 Hz


Option: 3

443 Hz


Option: 4

356 Hz


Answers (1)

best_answer

f=\frac{V}{4 l} \\

x=\frac{332}{4 \times 38 \times 10^{-2}} \\

x=\frac{332 \times 10^2}{4 \times 38} \\

x=\frac{332 \times 10^2}{152} \\

x=2.18 \times 10^2 \\

x=2.18 \times 100 \\

x=218 \mathrm{~Hz}

Posted by

chirag

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