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  • A tuning fork produces 10 beats per second with a sonometer wire of length 95cm and 100cm. The frequency of the fork is:Option: 1 380 Hz<br

A tuning fork produces 10 beats per second with a sonometer wire of length 95cm and 100cm. The frequency of the fork is:

Option: 1

380 Hz


Option: 2

390 Hz


Option: 3

340 Hz


Option: 4

300 Hz


Answers (1)

best_answer

\frac{n_{1}}{n_{2}} = \frac{100}{95} = \frac{20}{19}         (n_{1}>n_{2})

If the frequency of the tuning fork is x, for 10 beats per second,

n_{1} - x = 10 ; x - n_{2} = 0

Adding them,

n_{1} - n_{2} = 20

\frac{n_{1}}{n_{2}} - 1 = \frac{20}{n_{2}}

\frac{20}{19} - 1 = \frac{20}{n_{2}}

\frac{1}{19} = \frac{20}{n_{2}}

{n_{2}} = 380 Hz

Now,

x - {n_{2}} = 10

x = 10 + 380 = 390 Hz

Posted by

sudhir.kumar

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