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  • A uniform rod of mass is bent into the form of a semicircle of radius <img alt="\mathrm{R}" src="http

A uniform rod of mass \mathrm{m} is bent into the form of a semicircle of radius \mathrm{R}. The \mathrm{M I} of the rod about an axis passing through \mathrm{A} and perpendicular to the plane of the semicircle is-


 

Option: 1

\mathrm{\frac{2}{3} m R^2}
 


Option: 2

\mathrm{m R^2}
 


Option: 3

\mathrm{2 m R^2}
 


Option: 4

\mathrm{\frac{5}{\pi} m R^2}


Answers (1)

best_answer

\mathrm{I_A=M I} of the ring about tangent parallel to the axis-

\mathrm{I_A =I_{C m}+m d^2 }

\mathrm{ =m R^2+m R^2=2 m R^2 }

Hence option 3 is correct.

 

Posted by

Ritika Jonwal

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