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  • A uniform thin rod of mass ‘m’ and length L is held horizontally by two vertical strings attached to the two ends. One of the string is cut. Find the angular acceleration soon after it

A uniform thin rod of mass ‘m’ and length L is held horizontally by two vertical strings attached to the two ends. One of the string is cut. Find the angular acceleration soon after it is cut :

Option: 1

\frac{g}{2L}


Option: 2

\frac{g}{L}


Option: 3

\frac{3g}{2L}


Option: 4

\frac{2g}{L}


Answers (1)

best_answer

 

Analogue of second law of motion for pure rotation -

\vec{\tau }=I\, \alpha

- wherein

Torque equation can be applied only about two point

(i) centre of motion.

(ii) point which has zero velocity/acceleration.

 

 

Immediately after string connected to end B is cut, the rod has tendency to rotate about point A.

Torque on rod AB about axis passing through A and normal to plane of paper is 

                           \frac{ml^{2}}{3}\alpha =mg\frac{l}{2}\Rightarrow \alpha =\frac{3g}{2l}

 

                                                \alpha =\frac{3g}{2l}

 

Posted by

Divya Prakash Singh

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