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  • A uniform wire of length L, diameter D and density  is stretched under a tension T. The correct relation bet

A uniform wire of length L, diameter D and density \rho is stretched under a tension T. The correct relation between its fundamental frequency f, the length L and the diameter D is 

Option: 1

f \propto \frac{1}{L D}


Option: 2

f \propto \frac{1}{L \sqrt{D}}


Option: 3

f \propto \frac{1}{D^2}


Option: 4

f \propto \frac{1}{L D^2}


Answers (1)

best_answer

The fundamental frequency is f=\frac{1}{2 L} \sqrt{\frac{T}{\mu}}

f=\frac{1}{2 L} \sqrt{\frac{T}{\rho \pi \frac{D^2}{4}}}=\frac{1}{L D} \sqrt{\frac{T}{\pi \rho}} 

\therefore f \propto \frac{1}{L D}

Posted by

manish painkra

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