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A vertical tank, open at the top, is filled with a liquid and rests on a smooth horizontal surface. A small hole is opened at the centre of one side of the tank. The area of cross-section of the tank is N times the area of the hole, where \mathrm{N} is a large number. Neglect mass of the tank itself. The initial acceleration of the tank is

Option: 1

\mathrm{\frac{\mathrm{g}}{2 \mathrm{~N}}}


Option: 2

\mathrm{\frac{\mathrm{g}}{\sqrt{2} \mathrm{~N}}}


Option: 3

\mathrm{\frac{\mathrm{g}}{\mathrm{N}}}


Option: 4

\mathrm{\frac{\mathrm{g}}{2 \sqrt{\mathrm{N}}}}


Answers (1)

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\mathrm{\begin{aligned} &\text { Force }=\rho a(\sqrt{2 \mathrm{gh} / 2})^2\\ &\begin{aligned} & \text { acceleration. }=\frac{\rho \text { agh }}{\rho \mathrm{Na} \cdot \mathrm{H}} \\ & =\mathrm{g} / \mathrm{N} \end{aligned} \end{aligned}}

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Gautam harsolia

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