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  • A vessel of area of cross-section A has liquid to a height . There is a hole at the bottom of vessel h

A vessel of area of cross-section A has liquid to a height \mathrm{H}. There is a hole at the bottom of vessel having area of cross-section a. The time taken to decrease the level from \mathrm{H} 1 to \mathrm{H} 2 will be:

Option: 1

\mathrm{\frac{\mathrm{A}}{\mathrm{a}} \sqrt{\frac{2}{8}}\left[\sqrt{\mathrm{H}_1}-\sqrt{\mathrm{H}_2}\right]}


Option: 2

\mathrm{\sqrt{2 g h}}


Option: 3

\mathrm{\sqrt{2 \mathrm{gh}\left(\mathrm{H}_1-\mathrm{H}_2\right)}}


Option: 4

\mathrm{\frac{A}{a} \sqrt{\frac{g}{2}}\left[\sqrt{H_1}-\sqrt{H_2}\right]}


Answers (1)

best_answer

\mathrm{\mathrm{t}=\frac{\mathrm{A}}{\mathrm{a}}\left\{\sqrt{\frac{2 \mathrm{H}_1}{\mathrm{~g}}}-\sqrt{\frac{2 \mathrm{H}_2}{\mathrm{~g}}}\right\}}

Posted by

Riya

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