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A wave in a string has an amplitude of 2 cm. The wave travels in the + ve direction of x axis with a speed of 128 m/sec. and it is noted that 5 complete waves fit in 4 m length of the string. The equation describing the wave is:

Option: 1

y = (0.02) m sin (15.7x - 2010t)


Option: 2

y = (0.02) m sin (15.7x + 2010t)


Option: 3

y = (0.02) m sin (7.85x - 1005t)


Option: 4

y = (0.02) m sin (7.85x + 1005t)


Answers (1)

best_answer

As discussed in concept

Traveling Wave Equation -

y=A sin left ( Kx-omega t 
ight )
 

- wherein

K=2pi /lambda

omega = frac{2pi }{T}

lambda =  wavelength

T = The time period of oscillation

 

A = 2 cms,   v=\frac{\omega }{k}= 128ms-1 ,

5\lambda= 4, \lambda= 4/5

Y = A sin (kx - \omegat)

K = 2\pi / \lambda = 2\pi\times 5 / 4 = 7.85

\omega= 128 \times 7.85 = 1005

Y = 0.02 m sin ( 7.85x - 1005 t )

Posted by

Nehul

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