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  • A wire of length L is stretched by a length l when a force F is applied at one end. If the elastic limit is not exceeded, the amount of energy stored in the wire is given by<div

A wire of length L is stretched by a length l when a force F is applied at one end. If the elastic limit is not exceeded, the amount of energy stored in the wire is given by

Option: 1

\mathrm{F \times l}


Option: 2

\mathrm{1 / 2(F \times l)}


Option: 3

\mathrm{F l^2 / L}


Option: 4

\mathrm{1 / 2 F l^2 / L}


Answers (1)

best_answer

The force F can be assumed to act at the mid-point of the wire. Therefore, the average force responsible for extension is F / 2. Thus, the work done by the force \mathrm{\frac{F}{2}} to produce an extension l in the wire = force \times extension\mathrm{ =\frac{1}{2}(F \times l).} Hence the correct choice is (b).

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avinash.dongre

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