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Amongst the following elements (whose electronic configurations are given below), the one having the highest ionisation energy is.

Option: 1

\mathrm{[Ne] 3s^{2} 3p^{1}}
 


Option: 2

\mathrm{[Ne] 3s^{2} 3p^{3}}
 


Option: 3

\mathrm{[Ne] 3s^{2} 3p^{2}}
 


Option: 4

\mathrm{[Ar] 3d^{10} 4s^{2} 4p^{3}}


Answers (1)

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Option 1 and 3 are not stable electronic configuration due to absence of half-filled or fully-filled p-orbitals.

Option 2 and option 4 have half-filled p-orbitals. Therefore, they are more stable.
Among option 2 and option 4, the ionisation energy will be higher for configuration \mathrm{[Ne] 3s^{2} 3p^{3}} at option 2 is more stable than option 4 because of smaller atomic size.

Hence option 2 is correct.

Posted by

avinash.dongre

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