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  • An object is placed on the principal axis of a concave mirror at a distance of ( is the focal length). The image

An object is placed on the principal axis of a concave mirror at a distance of 1.5 f( f is the focal length). The image will be at,

Option: 1

1.5 f


Option: 2

-1.5 f


Option: 3

3f

 


Option: 4

-3f


Answers (1)

best_answer

u=-1.5f

focal length = f

\frac{1}{v}+\frac{1}{u}=\frac{1}{f}

\frac{1}{v}=\frac{1}{f}-\frac{1}{u}

\frac{1}{v}=\frac{1}{f}-\frac{1}{-1.5f}

\frac{1}{v}=\frac{1}{3f}

v=-3f

Posted by

Deependra Verma

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