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An object of mass '2kg' is rotating with angular velocity of '1rad/s' about an axis which is '1m' away from the centre of mass. If the radius of gyration of this object is '2m'. Then rotational kinetic energy of the body is given by 

Option: 1

5 Joule 


Option: 2

10 Joule


Option: 3

15 Joule


Option: 4

20 Joule


Answers (1)

best_answer

K_R=\frac{1}{2} I \omega^2

I=m d^2+m k^2

K_R=\frac{1}{2} m\left(d^2+k^2\right) \omega^2

K_R=\frac{1}{2} \times 2 \times(1+4) \times 1

K_R=5 \text { Joule }

Posted by

Shailly goel

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