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250 \, \mathrm{ml} aqueous solution of glucose win osmotic pressure 1.5 atm at 25^{\circ} \mathrm{C} is mixed with 420 \, \mathrm{ml} aqueous solution of urea of 3.6 \mathrm{~atm} at 25^{\circ} \mathrm{C}. What will be the osmotic pressure

Option: 1

2.81


Option: 2

3.56


Option: 3

4.27


Option: 4

5.64


Answers (1)

\mathrm{\pi_{1} V_{1}+\pi_{2} V_{2} =\pi R\left(V_{1}+V_{2}\right) }

\mathrm{\pi R =\frac{\pi_{1} V_{1}+\pi_{2} V_{2}}{V_{1}+V_{2}}}

\mathrm{\pi_{R} =\frac{1.5 \times 250+3.6 \times 420}{250+420}}

\mathrm{\pi_{R} =2.81}

Posted by

Kshitij

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