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  • At 500 K, the Root mean square ( rMs) speed of gas A [ Molar mass is 40] is equal to the most probable speed of gas B at 100 K. The molar mass of gas B is---- -<img alt="\mathrm{g mol}^{-1}" src="h

At 500 K, the Root mean square ( rMs) speed of gas A [ Molar mass is 40] is equal to the most probable speed of gas B at 100 K. The molar mass of gas B is---- -\mathrm{g mol}^{-1}

Option: 1

4 \mathrm{gmol}^{-\1}


Option: 2

0.1875 \mathrm{gmol}^{-\1}


Option: 3

0.28\mathrm{gmol}^{-\1}


Option: 4

0.3975\mathrm{gmol}^{-\1}


Answers (1)

best_answer

\mathrm{\begin{aligned} V r M S & =\sqrt{\frac{3 R T}{M}} \\ V M P & =\sqrt{\frac{2 R T}{M}} \\ \frac{V \text { rMS ot } A}{V M P \text { ot } B} & =\sqrt{\frac{3 T A M B}{2 T B M A}} \end{aligned}}

\mathrm{\begin{aligned} & 1=\sqrt{\frac{3 \times 500 \times M B}{2 \times 100 \times 40}} \\ & 1=\sqrt{\frac{M B \times 15}{80}} \end{aligned}}

\mathrm{1=\frac{15}{80} \times M B}

\mathrm{M B=\frac{80}{15}=.1875 \mathrm{gmol}^{-1}}

Posted by

Pankaj Sanodiya

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