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At  \small 100^{\circ}C a gas has 1 atm pressure and 10 L volume. Its volume (in L) at NTP would be -

Option: 1

10.9


Option: 2

7.8


Option: 3

15.3


Option: 4

12.14


Answers (1)

best_answer

Given,

At 100oC,P=1atm

                V=10L

At NTP,  T2 = 20oC

                P=1atm

So, Temperature in Kelvin,

\mathrm{T_1=373.15K,T_2=293.15K}

V_1=10,V_2=?

\frac{V_1}{T_1}=\frac{V_2}{T_2}\Rightarrow \frac{10}{373}=\frac{V_2}{293}

V_2=7.8  i.e less than 10L

 

 

Posted by

Pankaj Sanodiya

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