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  • At , the density of a gaseous oxide at 2 bar is

At \mathrm{0^{\circ} \mathrm{C}}, the density of a gaseous oxide at 2 bar is same as that of nitrogen at 5 bar. What is the molecular mass of the oxide?

Option: 1

60 \mathrm{~g} / \mathrm{mol}


Option: 2

70 \mathrm{~g} / \mathrm{mol}


Option: 3

75 \mathrm{~g} / \mathrm{mol}


Option: 4

65 \mathrm{~g} / \mathrm{mol}


Answers (1)

best_answer

Let, density of nitrogen and gaseous oxide be \mathrm{p_{1}} and \mathrm{p_{2}}
\mathrm{Using \, formula, \, p=\frac{P M}{R T}}

Pressure of nitrogen,                             molar mass of nitrogen,
\mathrm{ \quad P=5 \text { bar }=5 \times 0.987 \mathrm{~atm} . \quad M=28}.
 

\mathrm{\therefore p_{1} \text { (density of nitrogen) }=\frac{5 \times 0.987 \times 28}{R \times 273}}
\mathrm{ \therefore p_{2} \text { (density of gaseous oxide) }=\frac{2 \times 0.987 \times x}{R \times 273}}

As per question, both densities are equal at
\mathrm{ 0^{\circ} \mathrm{C}}

\mathrm{ \therefore \frac{2 \times 0.987 \times x}{R \times 273}=\frac{5 \times 0.987 \times 28}{R \times 273}}
\mathrm{ \Rightarrow x =\frac{5 \times 28}{2}=70 \mathrm{~g} / \mathrm{mol} \text { (option b) }}

Posted by

manish painkra

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